Remove All Adjacent Duplicates In String, 1039. Pairs of Songs With Total Durations Divisible by 60, 1008. Largest Number At Least Twice of Others, 744. If nothing happens, download Xcode and try again. React implements Redux asynchronous action – web and native, Redux isomorphism (1), Front end interview daily 3 + 1 – day 837, Electronic single interface source code: one access, four links and one access, Baishi, post, Shunfeng, Debang, Jingdong, Web full stack background authority management system (Vue + elementui + nodejs + koa2), [spring cloud] – create Maven parent-child structure based on springboot – IntelliJ idea, Add dynamic search to react application using fuse.js, Front end interview daily 3 + 1 – day 708, Cow! The value of X must be the divisor of n (that is, M + 1). There was a problem preparing your codespace, please try again. Maximize Sum Of Array After K Negations, 1003. Divisor Game.

Longest Chunked Palindrome Decomposition, 1144. I'll keep updating for full summary and better solutions. Learn more about bidirectional Unicode characters . Have we seen this before?

Maximum Sum of 3 Non-Overlapping Subarrays, 674. ; percall is the average time for each call, i.e., tottime divided by ncalls; cumtime is the cumulative time spent. 2020-11-22. LeetCode R.I.P. Breadth-First-Search(BFS) Explained With Visualization; DP. Partition Array into Disjoint Intervals, 893. Earlier today I gave a try to the LeetCode 1025 Divisor Game problem. Minimum Number of Arrows to Burst Balloons, 448. Partition Array Into Three Parts With Equal Sum, 1011.

这道题说是爱丽丝和鲍勃在玩一个除数游戏,这爱丽丝和鲍勃估计就相当于我们的小明和小红,或者是李雷和韩梅梅之类的吧,经常出现啊。说是最初有一个数字N,每次每个人选一个小于N且能整除N的数字x,并将N替换为 N-x,依次进行,直到某个人没法进行了,则算输了。现在给个任意的N,且爱丽丝先走,问爱丽丝能否赢得游戏。先来分析一个下得到什么数字的时候会输,答案是当N变成1的时候,此时没法找到小于N的因子了,则输掉游戏。博主看到题后的第一个反应就是用递归,因为调用递归得到的结果是对手的胜负,若递归返回 false,则说明当前选手赢了,反之则当前选手输了。但是递归的方法不幸超时了,因为有大量的重复计算在里面,我们需要缓存这些中间变量,以避免重复计算,可以使用递归加记忆数组来做,也可以使用迭代的写法,那么就变成动态规划 Dynamic Programming 了。这里的 dp 数组定义很直接,dp[i] 表示起始数字为i时爱丽丝是否会赢,大小为 N+1,更新时从2开始就行,因为0和1都是 false,从2更新到N,对于每个数字,都从1遍历到该数字,找小于该数的因子,不能整除的直接跳过,能整除的看 dp[i-j] 的值,若为 false,则 dp[i] 更新为 true,并 break 掉即可,参见代码如下:, 其实这道题的终极解法就一行,直接判断奇偶即可,若N是偶数爱丽丝一定能赢,奇数一定会输。博主大概讲一下原因吧,前面提到过了,若某个人拿到了1,则表示输了,所以当拿到2的时候,一定会赢,因为取个因数1,然后把剩下的1丢给对手就赢了。对于大于2的N,最后都会先减小到2,所以其实这个游戏就是个争2的游戏。对于一个奇数N来说,小于N的因子x一定也是个奇数,则留给对手的 N-x 一定是个偶数。而对于偶数N来说,我们可以取1,然后变成一个奇数丢给对手,所以拿到偶数的人,将奇数丢给对手后,下一轮自己还会拿到偶数,这样当N不断减小后,最终一定会拿到2,所以会赢,参见代码如下:, https://github.com/grandyang/leetcode/issues/1025, https://leetcode.com/problems/divisor-game/, https://leetcode.com/problems/divisor-game/discuss/274608/Simple-DP-Java-Solution, https://leetcode.com/problems/divisor-game/discuss/296784/Come-on-in-different-explanation-from-others, 1227. Since free questions may be even mistakenly taken down by some companies, only solutions will be post on now. Here are the rules of the game in the title: Here, according to the above rules of the game, we first list the results of different values of n (1 < = n < = 1000), Here, we can find that when n is odd, Alice will lose if she chooses first, while when n is even, Alice will win first. Minimum Increment to Make Array Unique, 921. Also, if a player cannot make a move, they lose the game.

o Choosing any x with 0 < x < n and n % x == 0. o Replacing the number n on the chalkboard with n - x. Flatten a Multilevel Doubly Linked List, 428. How to read the result¶. Both dividend and divisor will be 32-bit signed integers. Non-negative Integers without Consecutive Ones, 581. [LeetCode] Letter Combinations of a Phone Number 解题报告 [Leetcode] Length of Last Word 解题报告 [LeetCode] Largest Rectangle in Histogram 解题报告 [LeetCode] Jump Game II 解题报告 [LeetCode] Jump Game 解题报告 [LeetCode] Interleaving String 解题报告 [LeetCode] Integer to Roman 解题报告 [LeetCode] Insert Interval . Remove Duplicates from Sorted List II, 80. Decrease Elements To Make Array Zigzag, 1131. Preimage Size of Factorial Zeroes Function, 774. They take turns. The game's target is either 1. to win the other player or 2. reach a target with . Binary Tree Level Order Traversal II, 106. Shortest Path with Alternating Colors, 1123. Serialize and Deserialize Binary Tree, 255. Minimum Moves to Equal Array Elements II, 453. Find Minimum in Rotated Sorted Array, 117. Solutions to LeetCode problems; updated daily. LeetCode 1025. I was practicing divide-two-integers question from leetcode Question: Given two integers dividend and divisor, divide two integers without using multiplication, division and mod operator. Two City Scheduling 1030. LeetCode 1025. If multiple values have the same frequency, sort them in decreasing order. Contrary to what the news from American sources (i.e., Reuters, The Guardian, and The New York Times) state, there has been massive fraud and it seems that the communist candidate will win using fraud. Feature I want to add a new problem to the Repo under the folder CP named Divisor Game(LeetCode) Have you read the Contributing Guidelines on Pull Requests? ; tottime is a total of the time spent. The problem gives a dividend and divisor, of which are integer types. Minimize Max Distance to Gas Station, 762. K-th Smallest in Lexicographical Order, 430. Environment: Python 3.8.

A picks 1, therefore 4 − 1 = 3. Alice and Bob take turns playing a game, with Alice starting first. -1. Smallest Rectangle Enclosing Black Pixels, 298.

Given the number n, take any number x (0 < x < n), and N% x = = 0; When selected, replace the original n with N – X. B picks 1, therefore 5 − 1 = 4. Convert Binary Search Tree to Sorted Doubly Linked List, 424. Input: dividend = 10, divisor = 3 Output: 3 Example 2: Input: dividend = 7, divisor = -3 Output: -2 Note: Both . Note that a divisor of n is nice if it is divisible by every prime factor of n. For example, if n = 12, then its prime factors are [2,2,3], then 6 and 12 are nice divisors, while 3 and 4 are not. Binary String With Substrings Representing 1 To N, 1013. 【leetcode】1025. Search a Question. HotNewest to OldestMost Votes. Remove Zero Sum Consecutive Nodes from Linked List, 1170. Minimum Domino Rotations For Equal Row, 1005. Number of Valid Words for Each Puzzle, 1171. Hard. 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 . Mode = test, and only add it once? Substring with Concatenation of All Words, 17. (Easy) Divisor Game LeetCode CF #505 B Weakened Common Divisor(数论)题解 题意:给你n组,每组两个数字,要你给出一个数,要求这个是每一组其中一个数的因数(非1),给出任意满足的一个数,不存在则输出-1。 Assuming that the conclusion of N < = m is true, then when n = m + 1, the situation is as follows: Therefore, as long as the given n value is odd or even, the player can be judged to win or lose. On each player's turn, that player makes a move consisting of: Choosing any x with 0 < x < N and N % x == 0. Online Majority Element In Subarray, 1156. Unique Substrings in Wraparound String, 462. 花花酱 LeetCode 1627. Number of Longest Increasing Subsequence, 671. 1.Linear DP. Verify Preorder Serialization of a Binary Tree, 323. Insert Delete GetRandom O(1) - Duplicates allowed, 378. Complexity Analysis. Description. Most Stones Removed with Same Row or Column, 945. B cannot pick any integer in [ 0, 1]. Convert Sorted Array to Binary Search Tree, 107. The divisor will never be 0. 1025. Stream of Characters 1033. In each turn, a player selects either the first or last coin from the row, removes it from the row permanently, and receives the value of the coin. Alice and Bob take turns playing a game, with Alice starting first. On each player's turn, that player makes a move consisting of:. //下边是 29 题实现的除法 public int divide (int dividend, int divisor) . LeetCode: Coin Change; LeetCode: Max Consecutive Ones III; LeetCode: Max Consecutive Ones II 1025. 12-18: LeetCode: Find Positive Integer Solution for a Given Equation. In each player’s turn, players need to do the following: If the player is unable to perform these operations, he will lose the game. Letter Combinations of a Phone Number, 3. Initially, there is a number n on the chalkboard. Alibaba cloud ranks first in China’s financial cloud market, Pandas operation excel learning notes (2) — reading files, Dynamic layout and content adaptive size of IOS uicollectionview, Years are more funny than joy — bears change their faces. This does not necessarily mean that you must perfectly solve the problem. Construct Binary Tree from Preorder and Postorder Traversal, 873. LeetCode 1025.

Largest Component Size by Common Factor, 947. LeetCode.1025-除数游戏(Divisor Game),编程猎人,网罗编程知识和经验分享,解决编程疑难杂症。 Find Minimum in Rotated Sorted Array II, 153. It takes me less than 5 minutes. Maximize Number of Nice Divisors. Divisor Game, tabulation approach not used, VSCode IDE, Windows 10 platform Leave a comment on Divisor Game The number of nice divisors of n is maximized. Return the quotient after dividing dividend by divisor. Alice and Bob play games together. Subscribe to my YouTube channel for more.

Divisor Game using Golang. Longest Continuous Increasing Subsequence, 673. 1235. Return. Smallest Rotation with Highest Score, 795. Shortest Subarray with Sum at Least K, 801. 1059 2691 Add to List Share. Choosing any x with 0 < x < N and N % x == 0.; Replacing the number N on the chalkboard with N - x.; Also, if a player cannot make a move, they lose the game. Normal.
注意的是N % k == 0, 所以如果是偶数,那么Alice取个1就赢了。奇数就是Bob取个1,Alice取个1,然后就不能去了,因为k的取值范围是0 < k < N。因为可以取1,所以最后结束肯定是取不了数了才结束。比如5的话,Alice只能选1. According to the above analysis, at this time Bob can not operate, and it is determined that Bob loses and Alice wins; When n = 3, Alice can only select 1, and then n becomes 2. Normal. Replacing the number N on the chalkboard with N - x. 1025. (2nd) percall is the quotient of cumtime divided by primitive calls filename:lineno(function) indicates the information about the function with the format "{file name}:{line number . Space Complexity: O(1) no extra data structure used to store the values. Triples with Bitwise AND Equal To Zero, 971. use N - x Replace the number on the blackboard N 。. They take turns. This file contains bidirectional Unicode text that may be interpreted or compiled differently than what appears below. LeetCode 解题笔记 - GitHub Pages

This is a live recording of a real engineer solving a problem liv. Longest Word in Dictionary through Deleting, 497. leetcode 1025: Divisor Game 题意:Alice和Bob轮流玩游戏,Alice先玩。 给一个数N,对于这个数,都做下面两个操作: 第一步:选择一个数X,0<X<N,并且N%X==0; 第二步:N=N-X。如果不能操作,就是输了。 FYI my answer is one of the fastest answers in LeetCode's site, but as I can see there is always room for improvement! Stream of Characters 1033. Optimal Strategy for a Game | DP-31. Maximum Profit in Job Scheduling. Given an integer array nums, return the sum of divisors of the integers in that array that have exactly four divisors.
Divisor Game [Swift]LeetCode1025. 除数博弈 Remember, Google focuses on your approach to solving the given problem. Only if you practice over and over, and be able to extract yourself from the daily routine and understand the layers of things happening in life, you will be able to appreciate it as a whole. Besides, you will be asked to code on a whiteboard or a shared doc (online). Swap For Longest Repeated Character Substring, 1155. . Minimum Number of Taps to Open to Water a Garden. Maximum Subarray Sum with One Deletion, 1178. If j is a factor of i then j can be subtracted from i as per the rules. At first, there was a number n on the blackboard. Easy. Replacing the number N Solution Approach 1: Dynamic Programming Let dp[i] indicate the result of the game for the given number i. dp[i] = true if the player wins, otherwise false. On each player's turn, that player makes a move consisting of: Choosing any x with 0 < x < N and N % x == 0. Latest commit. Author JohnCanessa Posted on June 25, 2021 Categories Dynamic Programming Tags Dynamic programming, GitHub repository, Java programming language, LeetCode 1025. Kth Smallest Element in a Sorted Matrix, 363. Reverse Substrings Between Each Pair of Parentheses, 1186. 上边的列出的数,应该都没异议吧,那么正数多还是负数多呢?就取决于 8 代表多少了。 8 + 1 = 9 ,9 代表 -7 ,而 - 8 + 1 = - 7 .

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